résoudre dans R les équations suivantes

a) (3 x + 1)/2  + 3/4 = ((5/3) x) - 1  + 2 x

    ((3/2) x) + 1/2  + 3/4 = 11/3) x - 1

⇔ 11/3) x - (3/2) x = 1/2 + (3/4) + 1

⇔ 13/6) x = 9/4 ⇒ x = (9*6)/(4*13) ⇒ x = 27/26

b) 4 x - (5 x + 6)/6 = (3 x - 2)/18) - x/3

⇔ (24 x - 5 x - 6)/6 = (3 x - 2 - 6 x)/18

⇔ 19 x - 6)/6 = - 3 x - 2)/18

⇔ 3*(19 x - 6)/18 = - 3 x - 2)18

⇔ 57 x - 18 = - 3 x - 2

⇔ 60 x = 16 ⇒ x = 16/60⇒ x = 4/15

c) (5 x + 3)/3) + 1 = 2 x/15) - 2/5

⇔ 5 x/3 + 2 =2 x/15) - 2/5

⇔ 25 x - 2 x)/15 = - 2 - 2/5

⇔ 23 x/15 = - 30 - 6)/15

⇔ 23 x = - 36 ⇒ x = - 36/23