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FelipeJunior10
@FelipeJunior10
November 2019
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Calcule a soma dos 16 primeiros termos da PA (7, 14, ...) .
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Thihefi
Primeiro devemos calcular a razão da PA
r = a₂ - a₁ = 14 - 7 = 7
Calculo do enésimo termo:
a₁₆ = a₁ + (n-1).r
a₁₆ = 7 + (16 - 1).7
a₁₆ = 7 + 15.7
a₁₆ = 7 + 105
a₁₆ = 112
Agora calculamos a soma dos termos.
Sn = [(a₁ + an).n]/2
Sn = [(7 + 112).16]/2
Sn = 119 . 8
Sn = 952
=)
0 votes
Thanks 1
BrivaldoSilva
An=a1+ (n-1)*r
r= 14-7=7
a16=7+ (16-1).7
a16=7+15*7
a16=7+105=112
S16= (7+112)*16/2
S16 =119*8
S16=952
0 votes
Thanks 0
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Lista de comentários
r = a₂ - a₁ = 14 - 7 = 7
Calculo do enésimo termo:
a₁₆ = a₁ + (n-1).r
a₁₆ = 7 + (16 - 1).7
a₁₆ = 7 + 15.7
a₁₆ = 7 + 105
a₁₆ = 112
Agora calculamos a soma dos termos.
Sn = [(a₁ + an).n]/2
Sn = [(7 + 112).16]/2
Sn = 119 . 8
Sn = 952
=)
r= 14-7=7
a16=7+ (16-1).7
a16=7+15*7
a16=7+105=112
S16= (7+112)*16/2
S16 =119*8
S16=952