Calcule e justifique:.... Pergunta de ideia deLeonardo2424

August 2019 1 54 Report

Calcule e justifique:
$\lim_{x \to \ -1} \frac{x^{3}+1}{x^{2}-1}$

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Comentários (x+1)³=x³+3x²+3x+1
(x+1)³=x³+1+3x*(x+1)
x³+1 =(x+1)³-3x*(x+1)
x³+1=(x+1)*[(x+1)²-3x]
x³+1=(x+1)*[x²+2x+1-3x]
x³+1=(x+1)*(x²+1-x)

x²-1=(x+1)*(x-1)

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Lim (x+1)*(x²+1-x)/(x+1)*(x-1)
x-->-1

Lim (x+1)*(x²+1-x)/(x+1)*(x-1)
x-->-1

Lim (x²+1-x)/(x-1) =(1+1+1)/(-2) =-3/2
x-->-1

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Simplifique??????????

Simplifique: \frac{4x^{2}-9}{2x+3}

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