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SamuelPortillaaa
@SamuelPortillaaa
December 2019
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Como faço para resolver :
a) 2(3X-5) = 14
b)6-3X= -10-4X
c) 2x-1 sobre 5 = 3
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SupremoMacaco2
Vou responder de 1 em 1
2(3x-5)=14
3x-5=7
3x=7+5
3x=12
x=4
1 votes
Thanks 1
SupremoMacaco2
6-3x=-10-4x
SupremoMacaco2
-3x+4x=-10-6
SupremoMacaco2
x=-16
SupremoMacaco2
e a última
SupremoMacaco2
como assim sobre?
GowtherBr
Vamos lá:
a) 2(3x - 5) = 14
6x - 10 = 14
6x = 14 + 10
6x = 24
x = 24/6
x = 4
b)6 - 3x = - 10 - 4x
- 3x + 4x = - 10 - 6
x = - 16
c) 2x-1/5 = 3
Mmc (5,1) = 5
10x - 1 = 15
10x = 15 + 1
10x = 16
x = 16/10
x = 1,6
Espero ter ajudado !!!
1 votes
Thanks 0
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Lista de comentários
2(3x-5)=14
3x-5=7
3x=7+5
3x=12
x=4
a) 2(3x - 5) = 14
6x - 10 = 14
6x = 14 + 10
6x = 24
x = 24/6
x = 4
b)6 - 3x = - 10 - 4x
- 3x + 4x = - 10 - 6
x = - 16
c) 2x-1/5 = 3
Mmc (5,1) = 5
10x - 1 = 15
10x = 15 + 1
10x = 16
x = 16/10
x = 1,6
Espero ter ajudado !!!