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VanessaEster
@VanessaEster
January 2020
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Como resolvo essa equação exponencial 4^2x-1 ×2^4×=64 ??
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Alissonsk
Verified answer
4 ^ 2 x - 1 * 2 ^ 4 x = 64
( 2 ^ 2 ) ^ 2 x - 1 * 2 ^ 4 x = 2 ^ 6
2 ^ 4 x - 2 * 2 ^ 4 x = 2 ^ 6
2 ^ 8 x - 2 = 2 ^ 6
8 x - 2 = 6
8 x = 8
X = 1
Bons estudos!
1 votes
Thanks 1
VanessaEster
vlw !! ❤
Alissonsk
De nada!! ^^
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Lista de comentários
Verified answer
4 ^ 2 x - 1 * 2 ^ 4 x = 64( 2 ^ 2 ) ^ 2 x - 1 * 2 ^ 4 x = 2 ^ 6
2 ^ 4 x - 2 * 2 ^ 4 x = 2 ^ 6
2 ^ 8 x - 2 = 2 ^ 6
8 x - 2 = 6
8 x = 8
X = 1
Bons estudos!