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Becca173
@Becca173
January 2020
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Como resolvo essas equações do 2° grau a seguir?
a)2x²=0
b)4t²-1=0
c)3x²-7x=0
d)(√3) · t²=0
e)2t²-8=0
Ajudem-me, por favor!
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cintitamat
A) 2x^2 = 0
x^2 = 0/2
x^2 = 0
x = 0
b) 4t^2-1=0
4t^2 = 1
t^2 = 1/4
t = +- √1/4
t = +- 1/2
c) 3x^2-7x = 0
x (3x-7) = 0
x' = 0
3x-7=0
3x = 7
x'' = 7/3
d) √3t^2 = 0
t^2 = 0/√3
t^2 = 0
t = 0
e) 2t^2-8=0
2t^2 = 8
t^2 = 8/2
t^2 = 4
t = +- √4
t = +- 2
1 votes
Thanks 1
Becca173
Muito obrigada!!!!!!!!!!!!!!
cintitamat
bons estudos!
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x^2 = 0/2
x^2 = 0
x = 0
b) 4t^2-1=0
4t^2 = 1
t^2 = 1/4
t = +- √1/4
t = +- 1/2
c) 3x^2-7x = 0
x (3x-7) = 0
x' = 0
3x-7=0
3x = 7
x'' = 7/3
d) √3t^2 = 0
t^2 = 0/√3
t^2 = 0
t = 0
e) 2t^2-8=0
2t^2 = 8
t^2 = 8/2
t^2 = 4
t = +- √4
t = +- 2