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Barbosa125
@Barbosa125
November 2019
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Considere um quadro cuja diagonal mede 5√10cm.qual e a medida de cada lado desse quadrado
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5√10²=x²+x²
25.10=2x²
250=2x²
x²=250/2
x²=125
x=√125
x=√5².5
x=5√5 A area = 5√5²=25.5=125
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25.10=2x²
250=2x²
x²=250/2
x²=125
x=√125
x=√5².5
x=5√5 A area = 5√5²=25.5=125