Oi... Barbosa125
2) Aplicando Bhaskara:
x' = (-5 + √1)/2.1
x' = 6 / 2
x' = 3
x'' = (-5 - √1)/2.1
x'' = 4 / 2
x'' = 2
Bons estudos
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Oi... Barbosa125
Δ = b2 - 4.a.cΔ = -52 - 4 . 1 . 6
Δ = 25 - 4. 1 . 6
Δ = 1Há 2 raízes reais.
2) Aplicando Bhaskara:
x = ( -b +- √Δ)/2ax' = (-5 + √1)/2.1
x' = 6 / 2
x' = 3
x'' = (-5 - √1)/2.1
x'' = 4 / 2
x'' = 2
Bons estudos
= (-5)^2 - 4. 1. 6
= 25 - 24
= 1
X = -b +- (raiz de )/2a
X = 5 +- 1/ 2
X'= 5 + 1/ 2
X'= 6/2
X'= 3
X"= 5 - 1/2
X"= 4/2
X"= 2