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Marialuanetes2
@Marialuanetes2
November 2019
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Dada a função exponencial f(x) = 5 elevado a x
Calcule:
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ALCACARENHO
F(x) = 5^x
f(0) = 5^0 = 1
f(2) = 5² = 25
f(-1) = 5^-1 = 1/5
f(-3) = 5^-3 = 1/5³ = 1/ 125
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f(0) = 5^0 = 1
f(2) = 5² = 25
f(-1) = 5^-1 = 1/5
f(-3) = 5^-3 = 1/5³ = 1/ 125