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ThomasEdson001
@ThomasEdson001
August 2019
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Dada a Função f: R → R, por f(x)=3x²+2x determine o valor de f(-2)+f(3)+f(-1)
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RyanBriar
F(-2)= 3 (-2)^2 + 2 (-2)
f(-2)= 3 (4) + (-4)
f(-2)= 12 - 4
f(-2)= 8
f(3)= 3 (3)^2 + 2 x 3
f(3)= 3 (9) + 6
f(3)= 27 + 6
f(3)= 33
f(-1)= 3 (-1)^2 + 2 (-1)
f(-1)= 3 (1) + (-2)
f(-1)= 3 - 2
f(-1)= 1
f(-2) + f(3) + f(-1)
8 + 33 + 1 = 42
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f(-2)= 3 (4) + (-4)
f(-2)= 12 - 4
f(-2)= 8
f(3)= 3 (3)^2 + 2 x 3
f(3)= 3 (9) + 6
f(3)= 27 + 6
f(3)= 33
f(-1)= 3 (-1)^2 + 2 (-1)
f(-1)= 3 (1) + (-2)
f(-1)= 3 - 2
f(-1)= 1
f(-2) + f(3) + f(-1)
8 + 33 + 1 = 42