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Antonioulisses
@Antonioulisses
December 2019
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Dada a funçao f(x)=x2-x calcule: f(1)+3f(-1)-5f(3)+f(0)
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valsantina
F(1)= 1²- 1= 1 - 1= 0
f(-1)=(-1)²- (-1)= 1 + 1=2
f(3)= 3²- 3= 9 -3= 6
f(0)= 0²-0= 0
substituir em:
f(1)+3f(-1)-5f(3)+f(0)=
0 + 3. 2 - 5.6 +0=
6 - 30= -24
3 votes
Thanks 6
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Lista de comentários
f(-1)=(-1)²- (-1)= 1 + 1=2
f(3)= 3²- 3= 9 -3= 6
f(0)= 0²-0= 0
substituir em:
f(1)+3f(-1)-5f(3)+f(0)=
0 + 3. 2 - 5.6 +0=
6 - 30= -24