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DouglasHenrique0409
@DouglasHenrique0409
December 2019
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Dada a função por f(x)= x²-6x+9
Calcule
a) f(0)
b) f(1)
c) f(-2)
d) f(3)
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kaikvieira10
F(x)= x²-6x+9
a) f(0)
f(0) = x²-6x+9
f(0) = 0²-6.0+9
f(0) = 0 - 0 + 9
f(0) = 9
b) f(1)
f(1) = 1²-6.1+9
f(1) = 1 - 6 + 9
f(1) = -5 + 9
f(1) = 4
c) f(-2)
f(-2) = (-2)²-6.(-2)+9
f(-2) = 4 + 12 + 9
f(-2) = 25
d) f(3)
f(3) = 3²-6.3+9
f(3) = 9 - 18 + 9
f(3) = 0
Bons estudos !!! :-)
1 votes
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Lista de comentários
a) f(0)
f(0) = x²-6x+9
f(0) = 0²-6.0+9
f(0) = 0 - 0 + 9
f(0) = 9
b) f(1)
f(1) = 1²-6.1+9
f(1) = 1 - 6 + 9
f(1) = -5 + 9
f(1) = 4
c) f(-2)
f(-2) = (-2)²-6.(-2)+9
f(-2) = 4 + 12 + 9
f(-2) = 25
d) f(3)
f(3) = 3²-6.3+9
f(3) = 9 - 18 + 9
f(3) = 0
Bons estudos !!! :-)