Dados os complexos Z1 = 3 + 6i e Z2 = 5 - 4i, efetue: Z1.Z2
a) -12+14i
b) 25-12i
c) 15-24i
d) 39+18i
a) -12+14i
b) 25-12i
c) 15-24i
d) 39+18i
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Verified answer
(3 + 6i)( 5 - 4i)15-12i+30i-24i² =>
15+18i-24(-1) =>
15+18i+24=
39+18i
z=39+18i //
Letra D
Verified answer
Numero complexo voce multiplica normal. ( 3 +6i) ( 5 -4i) = 15 -12i + 30i - 24i^2 = 18i +39 , pois i^2= -1.