Determine o número de mols existentes em 180g de CaCO3 (MA:Ca = 40u, H =1u, 12u, O = 16u).... Pergunta de ideia deDanipereirarj

Danipereirarj @Danipereirarj

January 2020 1 30 Report

Determine o número de mols existentes em 180g de CaCO3 (MA:Ca = 40u, H =1u, 12u, O = 16u)

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Verified answer

Massa molar CaCO3 = 40 + 12 + 16 x 3 => 100 g/mol

1 mol CaCO3 ------------ 100 g
x mol CaCO3 ------------ 180 g

x = 180 . 1 / 100

x = 180 / 100

x = 1,8 mols

espero ter ajudado!

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