Articles
Register
Sign In
Search
Marcosphysique
@Marcosphysique
January 2020
1
33
Report
Determine X: A) 1=log3^x B) 0=log2^x C) log2^x=log2^5 D) log2x=log^6
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
guipocas
A)
log3^x = 1
x log3 = 1
x 0,48 = 1
x ~= 2,08
B)
log2^x = 0
x log2 = 0
x . 0,301 = 0
x = 0
C)
log2^x = log2^5
x log2 = 5 log2
x = 5
Eu acho que a D está enunciada de maneira errada, confira por favor.
0 votes
Thanks 0
More Questions From This User
See All
Marcosphysique
January 2020 | 0 Respostas
Responda
Marcosphysique
January 2020 | 0 Respostas
Responda
Marcosphysique
January 2020 | 0 Respostas
Responda
Marcosphysique
January 2020 | 0 Respostas
Preciso de ajuda com essas contas...
Responda
Marcosphysique
January 2020 | 0 Respostas
Responda
Marcosphysique
January 2020 | 0 Respostas
Determine X: 2log2(X+1)=3
Responda
Marcosphysique
August 2019 | 0 Respostas
Responda
Marcosphysique
May 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Determine X: A) 1=log3^x B) 0=log2^x C) log2^x=log2^5 D) log2x=log^6.... Pergunta de ideia de Marcosphysique"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
log3^x = 1
x log3 = 1
x 0,48 = 1
x ~= 2,08
B)
log2^x = 0
x log2 = 0
x . 0,301 = 0
x = 0
C)
log2^x = log2^5
x log2 = 5 log2
x = 5
Eu acho que a D está enunciada de maneira errada, confira por favor.