Efetuando , obtemos:A) B) C) D) E) Divirtam-se. :)).... Pergunta de ideia deIzzyKoushiro

April 2020 1 235 Report

Efetuando $\boxed{( \frac{1}{ \sqrt{3}-1} + \frac{1}{ \sqrt{3}+1 })^{-2}}$ , obtemos:

A) $4.$

B) $\frac{1}{4}.$

C) $3.$

D) $\frac{1}{3}.$

E) $2 \sqrt{3}$

Divirtam-se. :))

Lista de comentários

adrielcavalcant Observe que ...
$2^{-2} =( 2^{2})^{-1} = 4^{-1} = \frac{1}{4}$
Vai ser a mesma coisa aqui ...
$\frac{1}{ \sqrt{3} -1} = \frac{ \sqrt{3}+1}{2} \\
\\
 \frac{1}{ \sqrt{3} +1} = \frac{ \sqrt{3}-1}{2}\\\\
(\frac{ \sqrt{3}+1}{2} + \frac{ \sqrt{3}-1}{2})^{-2} = 
( \sqrt{3} )^{-2} = \frac{1}{3}$
Até mais !

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