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Pink78
@Pink78
December 2019
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Em h= - 4t² +8t +12, determine o instante após atingir 6 m de altura
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jvtavares
Boa tarde! Faremos esta questão tranquilamente, vamos passo a passo.
6 = -4t²-8t+12
-4t²-8t+6 = 0
Δ= 64 +64
Δ= 128
t= -1+1√2
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samarahelena001
A=4 ∆= 8²- 4×4×12
B=8 ∆= 64 - 192
C=12 ∆= -128
X= -8± √-128
–––––––
2× 4
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6 = -4t²-8t+12
-4t²-8t+6 = 0
Δ= 64 +64
Δ= 128
t= -1+1√2
B=8 ∆= 64 - 192
C=12 ∆= -128
X= -8± √-128
–––––––
2× 4