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Juhsilva1025
@Juhsilva1025
January 2020
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Equação do 2 grau como resolver com o bhaskara: h) 5x²-15x-50=0
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AnneP17
Vamos lá...
-b+- /b2 -4ac
a= 5
b= -15
c= -50
-(-15)+- /(-15)2 - 4.5.(-50)
15+- /225 - 20.(-50)
15+- /225 + 1000
15+- /1225
15+- 35
x| = 15 + 35= 50
x|| = 15 -35 = -20
Espero ter ajudado!
Bons estudos.
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Lista de comentários
-b+- /b2 -4ac
a= 5
b= -15
c= -50
-(-15)+- /(-15)2 - 4.5.(-50)
15+- /225 - 20.(-50)
15+- /225 + 1000
15+- /1225
15+- 35
x| = 15 + 35= 50
x|| = 15 -35 = -20
Espero ter ajudado!
Bons estudos.