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Juhsilva1025
@Juhsilva1025
January 2020
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Equaçao do 2 grau x²+4x+3=0
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metempsicose
A=1
b=4
c=3
delta=b^2-4.a.c
delta=4^2-4.1.3
delta=4
x=-b+-raiz delta/2.a
x=-4+-2/2
x'=-1
x"-3
1 votes
Thanks 2
sandyrafaela
X² + 4x + 3 = 0
Δ = b² - 4.a.c
Δ = 4² - 4.1.3
Δ = 16 - 12
Δ = 4
x = - b+- √Δ / 2.a
x = - 4 +- √4 / 2.1
x = - 4 +- 2 / 2
x' = - 4 + 2 / 2
= - 2 / 2
= - 1
x" = - 4 - 2 / 2
= - 6 / 2
= - 3
3 votes
Thanks 2
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Lista de comentários
b=4
c=3
delta=b^2-4.a.c
delta=4^2-4.1.3
delta=4
x=-b+-raiz delta/2.a
x=-4+-2/2
x'=-1
x"-3
Δ = b² - 4.a.c
Δ = 4² - 4.1.3
Δ = 16 - 12
Δ = 4
x = - b+- √Δ / 2.a
x = - 4 +- √4 / 2.1
x = - 4 +- 2 / 2
x' = - 4 + 2 / 2
= - 2 / 2
= - 1
x" = - 4 - 2 / 2
= - 6 / 2
= - 3