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LucasRibeiro1998
@LucasRibeiro1998
January 2020
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Escreva o binômio 6x+3 na forma (x+a)²-(x-b)².
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albertrieben
Ola Lucas
(x + a)² = x² + 2ax + a
²
(x - b)
² = x² - 2bx + b
²
x² + 2ax + a² - x² + 2bx - b² = 6x + 3
x*(2a + 2b) + a² - b² = 6x + 3
2a + 2b = 6
a + b = 3
a² - b² = 3
b = 3 - a
b² = 9 - 6a + a²
a² - 9 + 6a - a² = 3
6a = 3 + 9
a = 12/6 = 2
b = 3 - a = 3 - 2 = 1
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(x + a)² = x² + 2ax + a²
(x - b)² = x² - 2bx + b²
x² + 2ax + a² - x² + 2bx - b² = 6x + 3
x*(2a + 2b) + a² - b² = 6x + 3
2a + 2b = 6
a + b = 3
a² - b² = 3
b = 3 - a
b² = 9 - 6a + a²
a² - 9 + 6a - a² = 3
6a = 3 + 9
a = 12/6 = 2
b = 3 - a = 3 - 2 = 1