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BlackBeard
@BlackBeard
January 2021
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Hello,
On lance un dé à 6 faces. On suppose que la probabilité d’apparition de chaque face est proportionnelle au numéro inscrit
sur elle.
Calculer la probabilité d’apparition de chaque face.
Calculer la probabilité d’obtenir un nombre pair.
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croisierfamily
Verified answer
1 + 2 + 3 + 4 + 5 + 6 = 21
proba(1) = 1/21 = 0,o4762 = 4,76 %
p(2) = 2/21 = 0,o9524 = 9,52 %
p(3) = 3/21 = 1/7 = 0,14286 = 14,29 %
p(4) = 4/21 = 0,19o5 = 19,o5 %
p(5) = 5/21 = 0,2381 = 23,81 %
p(6) = 6/21 = 2/7 = 0,2857 = 28,57 %
TOTAL = 1oo % donc j' ai juste !
p(pair) = p(2;4;6) = 12/21 = 4/7 = 0,57143 = 57,14 % environ
p(impair) = 9/21 = 3/7 = 0,42857 = 42,86 %
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Verified answer
1 + 2 + 3 + 4 + 5 + 6 = 21proba(1) = 1/21 = 0,o4762 = 4,76 %
p(2) = 2/21 = 0,o9524 = 9,52 %
p(3) = 3/21 = 1/7 = 0,14286 = 14,29 %
p(4) = 4/21 = 0,19o5 = 19,o5 %
p(5) = 5/21 = 0,2381 = 23,81 %
p(6) = 6/21 = 2/7 = 0,2857 = 28,57 %
TOTAL = 1oo % donc j' ai juste !
p(pair) = p(2;4;6) = 12/21 = 4/7 = 0,57143 = 57,14 % environ
p(impair) = 9/21 = 3/7 = 0,42857 = 42,86 %