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AllanysKarolineLopes
@AllanysKarolineLopes
December 2019
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Inserir 6 meios aritméticos entre 4 e 53 contas pfvr
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baebergamota
Verified answer
A1=4
a8=53
an=a1+(n-1).r
53=4+(8-1).r
53=4+7r
53-4=7r
49=7r
r=49/7
r=7
a1=4
a2=4+7=11
a3=11+7=18
a4=18+7=25
a5=25+7=32
a6=32+7=39
a7=39+7=46
a8=46+7=53
1 votes
Thanks 1
allanepraia2
Verified answer
4,11,18,25,32,39,46,53.
r=7
Vai pela lógica !
0 votes
Thanks 1
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Lista de comentários
Verified answer
A1=4a8=53
an=a1+(n-1).r
53=4+(8-1).r
53=4+7r
53-4=7r
49=7r
r=49/7
r=7
a1=4
a2=4+7=11
a3=11+7=18
a4=18+7=25
a5=25+7=32
a6=32+7=39
a7=39+7=46
a8=46+7=53
Verified answer
4,11,18,25,32,39,46,53.r=7
Vai pela lógica !