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Liceoli
@Liceoli
January 2020
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L. Encontre o zero das funções:
a) f(x)= 5x+2
b) f(x)= 4x+16
c) f(x)= 15-3x
ll. Determine o zero da função quadrática:
f(x)= x²+3x-10
lll. Encontre as coordenadas do vértice da função: f(x)=2x²-4x+5
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Idws
Olá!
I- Substituir f(x) = 0
a)Ex: 5x+2 = 0 -> x=-2/5
b) -4
c) 3
II-Use Bhaskara:
x^2+3x-10 = 0
x= ( -b +-
) / 2a
x= -3 +-
/ 2.1
x= -3 +- 7 / 2
x'= 4/2 = 2
x''= -10/2 = -5
III - Vértices:
y= -Δ / 4a
y= (-4)^2 -(4.2.5) / 4.2
y= 16 - 40 / 8
y=-24 / 8
y=-3
x= -b /2a
x= -(-4) / 2.2
x= 4/4 = 1
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I- Substituir f(x) = 0
a)Ex: 5x+2 = 0 -> x=-2/5
b) -4
c) 3
II-Use Bhaskara:
x^2+3x-10 = 0
x= ( -b +- ) / 2a
x= -3 +- / 2.1
x= -3 +- 7 / 2
x'= 4/2 = 2
x''= -10/2 = -5
III - Vértices:
y= -Δ / 4a
y= (-4)^2 -(4.2.5) / 4.2
y= 16 - 40 / 8
y=-24 / 8
y=-3
x= -b /2a
x= -(-4) / 2.2
x= 4/4 = 1