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Zoukenziee
@Zoukenziee
May 2019
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Montrer que p(x)=x²-2x-3 peut se mettre sous la forme p(x)=(x-3)(ax+b)
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Commentaires (3)
P(x)= (x-3)(ax+b)
= ax^2+bx -3ax-3b
= ax^2 - (3a-b) x - 3b
= x^2 - 2 x - 3
a=1
3a-b=2
3b = 3 b=1
donc p(x)= (x-3)(x+1)
2 votes
Thanks 2
zoukenziee
p(x)= (x-3)(ax+b) = ax^2+bx -3ax-3b = ax^2 - (3a-b) x - 3b = x^2 - 2 x - 3 a=1 3a-b=2 3b = 3 b=1 donc p(x)= (x-3)(x+1)
zoukenziee
don c la réponse ?
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= ax^2+bx -3ax-3b
= ax^2 - (3a-b) x - 3b
= x^2 - 2 x - 3
a=1
3a-b=2
3b = 3 b=1
donc p(x)= (x-3)(x+1)