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DebiloideMatematico
@DebiloideMatematico
January 2020
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Na figura, o ângulo BCD mede 100°. Calcule a medida do ângulo ABD
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brenova97
100+2x=180
2x=180-100
2x=80
x=40
ABD=y
90-40=y
y=50
1 votes
Thanks 1
GabrielMagal1
Como o angulo BCD mede 100° e o triangulo é isosceles , CBD = CDB = 40° .
ABD+CBD = 90°
ABD+40° = 90°
ABD = 50°
1 votes
Thanks 0
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2x=180-100
2x=80
x=40
ABD=y
90-40=y
y=50
ABD+CBD = 90°
ABD+40° = 90°
ABD = 50°