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EduardoMontz
@EduardoMontz
December 2019
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O SERÁ NUMERO 2560 DEVÉRA SER DIVIDIDO EM PARTES INVERSAMENTES PROPORCIONAIS AOS 1\10 1\25 E 1\45.
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Verified answer
x y z
---- = ---- = ---- = k
10 25 45
x = 10k
y = 25k
z = 45k
10k + 25k + 45k = 80k
x + y + z = 2 560
80k = 2 560
k = 2 560 : 80
k = 32
x = 10. 32 ∴ x = 320
y = 25 . 32 ∴ y = 800
z = 45 . 32 ∴ z = 1 440
Resposta: 320, 800 e 1440
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Verified answer
x y z---- = ---- = ---- = k
10 25 45
x = 10k
y = 25k
z = 45k
10k + 25k + 45k = 80k
x + y + z = 2 560
80k = 2 560
k = 2 560 : 80
k = 32
x = 10. 32 ∴ x = 320
y = 25 . 32 ∴ y = 800
z = 45 . 32 ∴ z = 1 440
Resposta: 320, 800 e 1440