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Magno787
@Magno787
January 2020
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Obtenha o vértice de cada equação abaixo:
a)x2-4x+8=0
b)-x2+2x-5=0
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wagnerhenriquemarx
Xv = -b/2a ; Yv = -delta / 4a
a)
Xv = -b/2a => - (-4) / 2(1) => Xv = 2
Delta = 16 - 4(1)(8)
=> delta = -16
Yv = - delta / 4.a => -(-16) / 4.1 => Yv = 4
Vértice (2,4)
b)
Xv = -b/2a => -(2) / 2(-1) => Xv = 1
delta = 4 - 4(-1)(-5)
=> delta = -16
Yv = -(-16) / 4(-1) => Yv = -4
Vértice = (1,-4)
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Magno787
Mande o gráfico pra mim.
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a)
Xv = -b/2a => - (-4) / 2(1) => Xv = 2
Delta = 16 - 4(1)(8)
=> delta = -16
Yv = - delta / 4.a => -(-16) / 4.1 => Yv = 4
Vértice (2,4)
b)
Xv = -b/2a => -(2) / 2(-1) => Xv = 1
delta = 4 - 4(-1)(-5)
=> delta = -16
Yv = -(-16) / 4(-1) => Yv = -4
Vértice = (1,-4)