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Didisena16
@Didisena16
September 2019
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Como se utiliza a soma dos n termos da progressão geométrica? Alguém me explica com exemplo?
Fórmula:
Sn= a1 ( q^n - 1) / q -1
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marcilio69abreu
PG = [1, 2, 4, 8, 16]
q = 2/1 => q = 2
a1 = 1
a5 = 16
n = 5
S5 = a1 [2^(5-1)] / [2 - 1]
S5 = 1 [2^4] / 1
S5 = 2^4
S5 = 2*2*2*2
S5 = 16
1 votes
Thanks 1
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q = 2/1 => q = 2
a1 = 1
a5 = 16
n = 5
S5 = a1 [2^(5-1)] / [2 - 1]
S5 = 1 [2^4] / 1
S5 = 2^4
S5 = 2*2*2*2
S5 = 16