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Davidsouza16
@Davidsouza16
May 2020
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Qual a soma dos termos da Progressão Geométrica (9,27,...19683)
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Lucas7XD
Verified answer
An=a1.q^n-1
19683=9.3^n-1
19683=3².3^n-1
19683=3^(2+n-1) =>
19683=3^(1+n)
3^9=3^(1+n)
(1+n)=9
n=9-1
n=8 //
===================
Sn=a1.([q^n]-1) / q-1
Sn=9.([3^8]-1)/3-1
Sn=9.(6.561-1)/2 =>
Sn=9.6.560/2
Sn=59.040/2
Sn=29.520 //
Resposta:
29.520
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Lista de comentários
Verified answer
An=a1.q^n-119683=9.3^n-1
19683=3².3^n-1
19683=3^(2+n-1) =>
19683=3^(1+n)
3^9=3^(1+n)
(1+n)=9
n=9-1
n=8 //
===================
Sn=a1.([q^n]-1) / q-1
Sn=9.([3^8]-1)/3-1
Sn=9.(6.561-1)/2 =>
Sn=9.6.560/2
Sn=59.040/2
Sn=29.520 //
Resposta:
29.520