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Delayofgame2009
@Delayofgame2009
May 2020
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Uma nave espacial acelera a partir do repouso com aceleração de 10 m/s² numa linha reta.Quanto tempo,em dias,leva para que a nave atinja a velocidade de 3,6% da velocidade da luz? (c=3.10^8 m/s)
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nandofilho10
3,6% = 0,036
0,036 . 3.10⁸ = 0,108 .10⁸ m/s
V = Vo + at
0,108 .10⁸ = 0 + 10t
t =
dia --------- 86400s
x -----------0,108.10⁷ s
dias =
( 1 dia e meio )
2 votes
Thanks 6
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0,036 . 3.10⁸ = 0,108 .10⁸ m/s
V = Vo + at
0,108 .10⁸ = 0 + 10t
t =
dia --------- 86400s
x -----------0,108.10⁷ s
dias =
( 1 dia e meio )