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Jose38
@Jose38
December 2019
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Se a= 3i,b=2i e c=1+i, a b².c
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baebergamota
3i.(2i)^2.(1+i)=
3i.4i².(1+i)=
3i.4.(-1).(1+i)=
3i.-4.(1+i)=
-12i.(1+i)=
-12i-12i²=
-12i-12(-1)=
-12i+12=
12-12i
0 votes
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Lista de comentários
3i.4i².(1+i)=
3i.4.(-1).(1+i)=
3i.-4.(1+i)=
-12i.(1+i)=
-12i-12i²=
-12i-12(-1)=
-12i+12=
12-12i