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Wevertonevinho
@Wevertonevinho
January 2020
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Se fog(x)= 5x + 8 e f(x)= 2x + 2 qual o valor de g(-1) ?
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Tuck
Fog(x) = 5x + 8 é o mesmo que;
f(g(x)) = 5x + 8
------------------------------
f(x) = 2x + 2
f(g(x)) = 2g(x) + 2
5x + 8 = 2g(x) + 2
5x + 8 - 2 = 2g(x)
5x + 6 = 2g(x)
g(x) = (5x + 6)/2
-------------------------
g(-1) = (5(-1) + 6)/2
g(-1) = (-5 + 6)/2
g(-1) = 1/2
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f(g(x)) = 5x + 8
------------------------------
f(x) = 2x + 2
f(g(x)) = 2g(x) + 2
5x + 8 = 2g(x) + 2
5x + 8 - 2 = 2g(x)
5x + 6 = 2g(x)
g(x) = (5x + 6)/2
-------------------------
g(-1) = (5(-1) + 6)/2
g(-1) = (-5 + 6)/2
g(-1) = 1/2