Articles
Register
Sign In
Search
GhostWalk
@GhostWalk
November 2019
2
157
Report
Se Tag (α) = 2, então Sen (2α) é igual a?
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
brenoreis17
0 votes
Thanks 2
GhostWalk
Por gentileza, teria como você dar uma olhada em outra pergunta minha? Agradeço por essa :)
brenoreis17
Com todo o prazer.
albertrieben
Boa noite
tg(α) = 2
sen(2α) = 2sen(α)*cos(α)
sen(α) = tg(α)/√[1 + tg²(α)]
sen(α) = 2/√[1 + 4] = 2√5/5
cos(α) = 1/√[1 + tg²(α)]
cos(α) = 1/√[1 + 4] = √5/5
sen(2α) = 2sen(α)*cos(α)
sen(2α) = 2"2√5/5*√5/5 = 4/5
2 votes
Thanks 1
More Questions From This User
See All
GhostWalk
November 2019 | 0 Respostas
Responda
GhostWalk
November 2019 | 0 Respostas
Responda
GhostWalk
November 2019 | 0 Respostas
Responda
GhostWalk
November 2019 | 0 Respostas
Responda
GhostWalk
November 2019 | 0 Respostas
Responda
GhostWalk
November 2019 | 0 Respostas
Responda
GhostWalk
November 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "Se Tag (α) = 2, então Sen (2α) é igual a?.... Pergunta de ideia de GhostWalk"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
tg(α) = 2
sen(2α) = 2sen(α)*cos(α)
sen(α) = tg(α)/√[1 + tg²(α)]
sen(α) = 2/√[1 + 4] = 2√5/5
cos(α) = 1/√[1 + tg²(α)]
cos(α) = 1/√[1 + 4] = √5/5
sen(2α) = 2sen(α)*cos(α)
sen(2α) = 2"2√5/5*√5/5 = 4/5