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GhostWalk
@GhostWalk
November 2019
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Se Tag (α) = 2, então Sen (2α) é igual a?
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brenoreis17
0 votes
Thanks 2
GhostWalk
Por gentileza, teria como você dar uma olhada em outra pergunta minha? Agradeço por essa :)
brenoreis17
Com todo o prazer.
albertrieben
Boa noite
tg(α) = 2
sen(2α) = 2sen(α)*cos(α)
sen(α) = tg(α)/√[1 + tg²(α)]
sen(α) = 2/√[1 + 4] = 2√5/5
cos(α) = 1/√[1 + tg²(α)]
cos(α) = 1/√[1 + 4] = √5/5
sen(2α) = 2sen(α)*cos(α)
sen(2α) = 2"2√5/5*√5/5 = 4/5
2 votes
Thanks 1
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Lista de comentários
tg(α) = 2
sen(2α) = 2sen(α)*cos(α)
sen(α) = tg(α)/√[1 + tg²(α)]
sen(α) = 2/√[1 + 4] = 2√5/5
cos(α) = 1/√[1 + tg²(α)]
cos(α) = 1/√[1 + 4] = √5/5
sen(2α) = 2sen(α)*cos(α)
sen(2α) = 2"2√5/5*√5/5 = 4/5