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Fabiziinhabs
@Fabiziinhabs
December 2019
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Sendo log 2= a e log 3= b, calcule o valor de:
a) log 15
b) log 0,75
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jonataslaet
a)
log 15 = log (3*5) = log (3) + log (5)
b + log (10/2) = b + log (10) - log (2)
b + 1 - a; portanto
log (15) = b + 1 - a
b)
log (0,75) = log (4/3) = log (4) - log (3)
log (2*2) - b = log (2) + log (2) - b
a + a - b; portanto
log (0,75) = 2*a - b
3 votes
Thanks 2
fabiziinhabs
Você poderia me explicar o passo a passo, estou um pouco confusa, primeiro você utilizou a propriedade e depois ?
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Lista de comentários
log 15 = log (3*5) = log (3) + log (5)
b + log (10/2) = b + log (10) - log (2)
b + 1 - a; portanto log (15) = b + 1 - a
b)
log (0,75) = log (4/3) = log (4) - log (3)
log (2*2) - b = log (2) + log (2) - b
a + a - b; portanto log (0,75) = 2*a - b