Sendo log 2 na base 10 = 0,301, o número de algarismos de 5^20 é? a) 13 b) 14 c) 19 D) 20 e) 27.... Pergunta de ideia deCarolineAraki

CarolineAraki @CarolineAraki

January 2020 1 123 Report

Sendo log 2 na base 10 = 0,301, o número de algarismos de 5^20 é?
a) 13
b) 14
c) 19
D) 20
e) 27

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ghvalves Número de algarismos de 5^20 = E[ log (5^20)] +1 = E[20· log5]+1 =
E[ 20· log(10/2)] +1= E[ 20· (log10- log2)] +1=
E[20· (1- 0,301)] +1= E[20· 0,699] +1= E[13,98] +1 = 13 + 1= 14 algarismos

1 votes Thanks 1

ghvalves sendo assim alternativa b

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