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BelleCampos314
@BelleCampos314
September 2019
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Sendo (x+y)^2 = 81 e x^2 + y^2 = 53 , calcule XY
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jvsilvictorox7rfj
(x + y) ² = 81
x² + y² = 53
Sabemos que:
(x + y)² = x² + 2xy + y²
Sendo assim, teremos:
x² + 2xy + y² = 81
Substituindo o valor de "x² + y²":
53 + 2xy = 81
2xy = 81 - 53
2xy = 28
xy = 28/2
xy = 14
>>Resposta:
xy = 14.
3 votes
Thanks 1
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Lista de comentários
x² + y² = 53
Sabemos que:
(x + y)² = x² + 2xy + y²
Sendo assim, teremos:
x² + 2xy + y² = 81
Substituindo o valor de "x² + y²":
53 + 2xy = 81
2xy = 81 - 53
2xy = 28
xy = 28/2
xy = 14
>>Resposta: xy = 14.