Sendo n um número natural, a expressão [tex] \frac{ (2^{n+1} + 2^{n+2} ) . ( 3^{n+2} - 3^{n-1}) }{ 6^{n+2} } [/tex] é igual a:
a) 1
b) [tex] 3^{n} [/tex]
c) [tex] 2^{n} [/tex]
d) [tex] 6^{n} [/tex]
e) 6
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