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cassiiagabriela16
@cassiiagabriela16
October 2020
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[tex] \left \{ {{x^2-4x+3 \leq 0} \atop {x^2-7x+10>0}} \right. [/tex]
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emicosonia
x²- 4x + 3
<
0
Δ=b²-4ac
Δ=(-4)²-4(1)(3)
Δ=16-12
Δ=4 >0
x1=
-b-√Δ -(-4) - √4 4 - 2 2 1 3
---------- = --------------- = ---------------- = --------- = 1 | |
2a 2(1) 2 2 + | | +
-------•\/\/\/•-------
x2 =
-b+√Δ -(-4) + √4 4+2 6 \ - /
------------- = ----------------- = ---------- = ---------- = 3
2a 2(1) 2 2
V={x∈R| 1 ≤ x ≤ 3}
=
[1;3]
x² - 7x +10 > 0
Δ=b²-4ac
Δ=(-7)²-.4(1)(10)
Δ=49 - 40
Δ=9 > 0
x1= -b-√Δ -(-7) -√9 7 - 3 4 2 5
---------- = --------------- = ---------- = ------ = 2 | |
2a 2(1) 2 2 + | | +
/\/\/\/\•-------•/\/\/\/\/\/\
x2= -b+√Δ -(-7) +√9 7+3 10 \ - /
----------- = ---------------- = ------------ = ----------- = 5
2a 2(1) 2 2
V={x∈R|x≤2 ou x≥5} = ]-∞;2] U [5;+∞[
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Resolver a equacao 5 + |-2x+4| =11
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x²- 4x + 3< 0
Δ=b²-4ac
Δ=(-4)²-4(1)(3)
Δ=16-12
Δ=4 >0
x1= -b-√Δ -(-4) - √4 4 - 2 2 1 3
---------- = --------------- = ---------------- = --------- = 1 | |
2a 2(1) 2 2 + | | +
-------•\/\/\/•-------
x2 = -b+√Δ -(-4) + √4 4+2 6 \ - /
------------- = ----------------- = ---------- = ---------- = 3
2a 2(1) 2 2
V={x∈R| 1 ≤ x ≤ 3} = [1;3]
x² - 7x +10 > 0
Δ=b²-4ac
Δ=(-7)²-.4(1)(10)
Δ=49 - 40
Δ=9 > 0
x1= -b-√Δ -(-7) -√9 7 - 3 4 2 5
---------- = --------------- = ---------- = ------ = 2 | |
2a 2(1) 2 2 + | | +
/\/\/\/\•-------•/\/\/\/\/\/\
x2= -b+√Δ -(-7) +√9 7+3 10 \ - /
----------- = ---------------- = ------------ = ----------- = 5
2a 2(1) 2 2
V={x∈R|x≤2 ou x≥5} = ]-∞;2] U [5;+∞[