[tex] \left \{ {{x^2-4x+3 \leq 0} \atop {x^2-7x+10>0}} \right. [/tex].... Pergunta de ideia decassiiagabriela16

October 2020 1 73 Report

[tex] \left \{ {{x^2-4x+3 \leq 0} \atop {x^2-7x+10>0}} \right. [/tex]

Lista de comentários

emicosonia

x²- 4x + 3< 0
Δ=b²-4ac
Δ=(-4)²-4(1)(3)
Δ=16-12
Δ=4 >0

x1= -b-√Δ   -(-4) - √4   4 - 2 2 1 3
---------- = --------------- = ---------------- = --------- = 1 |      |
2a 2(1) 2 2       +    | | +
-------•\/\/\/•-------
x2 = -b+√Δ -(-4) + √4 4+2 6 \ -  /
------------- = ----------------- = ---------- = ---------- = 3
2a 2(1) 2 2

V={x∈R| 1 ≤ x ≤ 3} = [1;3]

x² - 7x +10 > 0
Δ=b²-4ac
Δ=(-7)²-.4(1)(10)
Δ=49 - 40
Δ=9 > 0

x1= -b-√Δ -(-7) -√9 7 - 3 4 2 5
---------- = --------------- = ---------- = ------ = 2 | |
2a 2(1) 2 2 + | | +
/\/\/\/\•-------•/\/\/\/\/\/\
x2= -b+√Δ -(-7) +√9 7+3 10 \ - /
----------- = ---------------- = ------------ = ----------- = 5
2a 2(1) 2 2

V={x∈R|x≤2 ou x≥5} = ]-∞;2] U [5;+∞[

Lista de comentários

Resolver a equacao 5 + |-2x+4| =11

Helpful Links

Helpful Social