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cassiiagabriela16
@cassiiagabriela16
October 2020
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resolver [tex] \frac{x^2-4x-5}{x-2} > 0 [/tex]
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3478elc
Verified answer
e x ≠ 2
x² - 4x - 5 = 0
Δ = (-4)² - 4.1.(-5) = 16 + 20 = 36
x = 4 +/-√36 ==> x = 4+/-6
2.1 2
x1 = 4+6==> x1 = 5
2
x2 = 4-6==> x2 = - 1
2
- 1 2 5
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{ x ∈ R / - 1 < x < 2 ou x > 5 }
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Resolver a equacao 5 + |-2x+4| =11
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Verified answer
e x ≠ 2x² - 4x - 5 = 0
Δ = (-4)² - 4.1.(-5) = 16 + 20 = 36
x = 4 +/-√36 ==> x = 4+/-6
2.1 2
x1 = 4+6==> x1 = 5
2
x2 = 4-6==> x2 = - 1
2
- 1 2 5
- | + | + | +
- | - | + | +
- | - | - | +
- + - +
{ x ∈ R / - 1 < x < 2 ou x > 5 }