Conjunto soluçãao [tex] \frac{x^2-4x-5}{x^2-12x+20} < 0 [/tex].... Pergunta de ideia decassiiagabriela16

cassiiagabriela16 @cassiiagabriela16

October 2020 1 79 Report

Conjunto soluçãao
[tex] \frac{x^2-4x-5}{x^2-12x+20} < 0 [/tex]

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3478elc

Verified answer

x² - 4x - 5 = 0

Δ = (-4)² - 4.1.(-5) = 16 + 20 = 36

x = 4 +/-√36 ==> x = 4+/-6
2.1 2

x1 = 4+6==> x1 = 5
2

  x2 = 4-6==> x2 = - 1
2

x² - 12x + 20 ≠ 0

Δ = (-12)² - 4.1.(20) = 144 - 80 = 64

x = 12 +/-√64 ==> x = 12+/-8
2.1 2

x1 = 12+8==> x1 = 10
2

  x2 = 12-8==> x2 = 1
  2

    - 1 1 5 10
    - | + | + | + | +
    - | - | + | + | +
   -  | - | - | +   | +
- | - | - | -   |   +
+ - + - +

V = { x ∈ R / - 1 < x < 1 ou 5 < x < 10 }

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Resolver a equacao 5 + |-2x+4| =11

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