Articles
Register
Sign In
Search
cassiiagabriela16
@cassiiagabriela16
October 2020
2
73
Report
me ajude com essa inequação
[tex] \frac{2}{x-1} < 1 [/tex]
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
3478elc
Verified answer
, x ≠ 1
2 < x - 1
- x < - 1 - 2
- x < - 3(-1)
x > 3
V = {x∈ ∈R / x > 3 e x ≠ 1 }
1 votes
Thanks 1
ProfAmaral
Condição de existência: x - 1 ≠ 0
x ≠ 0 + 1
x ≠ 1
2
< 1
x - 1
2 < 1 · (x - 1)
2 < x - 1
2 + 1 < x
3 < x
x > 3
S = {x ∈ R/ x > 3}
1 votes
Thanks 1
More Questions From This User
See All
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
[tex] \left \{ {{x^2-4x+3 \leq 0} \atop {x^2-7x+10>0}} \right. [/tex]
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Responda
cassiiagabriela16
October 2020 | 0 Respostas
Resolver a equacao 5 + |-2x+4| =11
Responda
×
Report "me ajude com essa inequação[tex] \frac{2}{x-1} < 1 [/tex].... Pergunta de ideia de cassiiagabriela16"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
, x ≠ 1
2 < x - 1
- x < - 1 - 2
- x < - 3(-1)
x > 3
V = {x∈ ∈R / x > 3 e x ≠ 1 }
x ≠ 0 + 1
x ≠ 1
2 < 1
x - 1
2 < 1 · (x - 1)
2 < x - 1
2 + 1 < x
3 < x
x > 3
S = {x ∈ R/ x > 3}