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Luana15161
@Luana15161
January 2020
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Um triângulo retângulo com cateto medindo 6cm e hipotenusa 10cm, quanto mede o outro cateto?
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gimoeller
A = hipotenusa (10cm)
b = cateto (6cm)
c = cateto (x cm)
a^ = b^ + c^
10^ = 6^ + c^
100 = 36 + c^
c^ = 100 - 36
c ^ = 64
c = Raiz de 64
c = 8
R: Mede 8cm.
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Comentários
H^2=C^2+C^2
10^2=6^2+C^2
C^2=100-36
C=8
0 votes
Thanks 2
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b = cateto (6cm)
c = cateto (x cm)
a^ = b^ + c^
10^ = 6^ + c^
100 = 36 + c^
c^ = 100 - 36
c ^ = 64
c = Raiz de 64
c = 8
R: Mede 8cm.
10^2=6^2+C^2
C^2=100-36
C=8