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BRU2705
@BRU2705
December 2019
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Usando a aproximação cos 25 = 9 sobre 10, determine o valor de:
a) sen 25
b) tg 25
c) sen 65
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A) sen^2 x + cos^2x =1
sen^2 x + 9/10=1
sen^2 x=1-9/10
sen^2 x= 1/10
senx=√1/10
senx=1/√10 * √10/√10
1*√10/√10*√10=√10/10
b) tgx=√10/10/9/10=√10/10*10/9=√10/9
c) sen65=0,9
espero ter ajudado
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sen^2 x + 9/10=1
sen^2 x=1-9/10
sen^2 x= 1/10
senx=√1/10
senx=1/√10 * √10/√10
1*√10/√10*√10=√10/10
b) tgx=√10/10/9/10=√10/10*10/9=√10/9
c) sen65=0,9
espero ter ajudado