Me ajudem com essa conta!?3x/2x-6 + 1= 4x/x-3.... Pergunta de ideia deBarbaraerescov

Barbaraerescov @Barbaraerescov

April 2020 1 24 Report

Me ajudem com essa conta!?
3x/2x-6 + 1= 4x/x-3

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PeH $\bullet \ \frac{3x}{2x - 6} + 1 = \frac{4x}{x - 3} \\\\
\frac{3x}{2x - 6} + \frac{2x - 6}{2x - 6} = \frac{4x}{x - 3} \\\\
\frac{5x - 6}{2x - 6}= \frac{4x}{x - 3} \\\\
(5x - 6) \cdot (x - 3) = 4x \cdot (2x - 6) \\\\
5x^2 - 15x - 6x + 18 = 8x^2 - 24x \\\\
5x^2 - 21x + 18 = 8x^2 - 24x \\\\
3x^2 - 3x - 18 = 0 \\\\
x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\
x = \frac{3 \pm \sqrt{9 - 4 \cdot 3 \cdot (-18)}}{2 \cdot 3} \\\\
x = \frac{3 \pm \sqrt{225}}{6}[tex]\\[tex]x = \frac{3 \pm 15}{6} \\\\ x_{1} = \frac{3 + 15}{6} = 3 \\\\ x_{2} = \frac{3 - 15}{6} = -2 \\\\
\boxed{\text{S} = \{ -2 ; 3 \}$

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