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Analuiz4s
@Analuiz4s
May 2020
2
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(x-4)²+5x(x-1)=16
como eu faço isso???
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3478elc
Verified answer
(x-4)²+5x(x-1)=16
x^2 - 8x + 16 + 5x^2 - 5x - 16 = 0
6x^2 - 13x = 0 eq.incompleta
x( 6x - 13 ) = 0
x1 = 0
6x2 - 13 = 0
6x2 = 13
x2 = 13
6
V = { 0, 13/6 }
8 votes
Thanks 20
sarahkl30
(x-4)²+5x(x-1)=16(x-4).(x-4)+5x(x-1)=16
x²-4x-4x+16+5x²-5x=16
6x²-8x+16-16=0
6x²-13x=0
a=6
b=-13
c=0
b²-4.a.c
-13²-4.6.0
169
x=-b+-
√169/2.a
x=-(-13)+-13/2.6
x=26/12
x=13/6
o outro resultado não vale pq fica 0/12.
6 votes
Thanks 12
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Lista de comentários
Verified answer
(x-4)²+5x(x-1)=16
x^2 - 8x + 16 + 5x^2 - 5x - 16 = 0
6x^2 - 13x = 0 eq.incompleta
x( 6x - 13 ) = 0
x1 = 0
6x2 - 13 = 0
6x2 = 13
x2 = 13
6
V = { 0, 13/6 }
x²-4x-4x+16+5x²-5x=16
6x²-8x+16-16=0
6x²-13x=0
a=6
b=-13
c=0
b²-4.a.c
-13²-4.6.0
169
x=-b+-√169/2.a
x=-(-13)+-13/2.6
x=26/12
x=13/6
o outro resultado não vale pq fica 0/12.