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EnjoyPhenix
@EnjoyPhenix
April 2019
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Pouvez-vous m'aider pour trouver la dérivée de f définie par et m'expliquer un peu svp :
f(x)=(2x(x-1))/(x+1)²
Merci :)
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LucasBonnet
La formule de dérivation de (u/v) est (u/v)' = (u'v - v'u)/v²
Tu poses u(x) = 2x(x-1) = 2x² - 2x
et v(x) = (x+1)² = x² + 2x + 1
donc u'(x)= 4x - 2 et v'(x) = 2x + 2
(u/v)' = (u'v - v'u) / v² donc
après développement et réduction ça donne :
et voilà tu as ta dérivée ;)
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Tu poses u(x) = 2x(x-1) = 2x² - 2x
et v(x) = (x+1)² = x² + 2x + 1
donc u'(x)= 4x - 2 et v'(x) = 2x + 2
(u/v)' = (u'v - v'u) / v² donc
après développement et réduction ça donne :
et voilà tu as ta dérivée ;)