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SugaSugar
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November 2019
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(FGV). Sendo x = 2, 771 e y = 0, 271 qual é o valor numérico de X^3-y^3/X^2+XY+Y^2
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albertrieben
Boa noite
x^3 - y^3 = (x - y) (x^2 + xy + y^2)
E = (x^3 - y^3 )/(x^2 + xy + y^2) = (x - y) (x^2 + xy + y^2)/ (x^2 + xy + y^2)
E = x - y = 2,771 . 0,271 = 2.5
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x^3 - y^3 = (x - y) (x^2 + xy + y^2)
E = (x^3 - y^3 )/(x^2 + xy + y^2) = (x - y) (x^2 + xy + y^2)/ (x^2 + xy + y^2)
E = x - y = 2,771 . 0,271 = 2.5