Resolvidas as questões, os resultados obtidos foram:
[tex]1) C\\\\2) A\ (Maior\ que\ zero)\\\\3) A\\\\4) B\\\\5) E\\\\[/tex]
1) As raízes da equação podem ser calculadas pelo método da soma e
produto.
[tex]x^2 - 4x + 4 = 0\\\\a = 1\\\\b = -4\\\\c = 4\\\\S = -b / a\\\\S = 4 / 1\\\\S = 4\\\\P = c / a\\\\P = 4 / 1\\\\P = 4\\\\[/tex]
A equação admite raiz única e igual a [tex]2, pois\ 2 + 2 = 4\ e\ 2.2 = 4\\[/tex]
[tex]2) 2x^2 - 3x - 4 = 0\\\\\Delta = b^2 - 4ac\\\\\Delta = (-3)^2 - 4.1.(-4)\\\\\Delta = 9 + 16\\\\\Delta = 25\\\\[/tex]
3) Nesta questão deve ser a soma dos coeficiente igual a 4.
[tex]x^2 + 2x + 1\\\\1 + 2 + 1\\\\3 + 1\\\\4\\[/tex]
[tex]4) x^2 - 4x = 0\\\\x.(x - 4) = 0\\\\x = 0\\\\x - 4 = 0\\\\x = 4\\\\(0 , 4)\\\\[/tex]
[tex]5) x^2 - 4 = 0\\\\x^2 = 4\\\\x = \pm\sqrt{4}\\ \\x = \pm2\\\\(2 ; -2)\\[/tex]
Veja mais em:
https://brainly.com.br/tarefa/18744845
https://brainly.com.br/tarefa/292422
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Resolvidas as questões, os resultados obtidos foram:
[tex]1) C\\\\2) A\ (Maior\ que\ zero)\\\\3) A\\\\4) B\\\\5) E\\\\[/tex]
1) As raízes da equação podem ser calculadas pelo método da soma e
produto.
[tex]x^2 - 4x + 4 = 0\\\\a = 1\\\\b = -4\\\\c = 4\\\\S = -b / a\\\\S = 4 / 1\\\\S = 4\\\\P = c / a\\\\P = 4 / 1\\\\P = 4\\\\[/tex]
A equação admite raiz única e igual a [tex]2, pois\ 2 + 2 = 4\ e\ 2.2 = 4\\[/tex]
[tex]2) 2x^2 - 3x - 4 = 0\\\\\Delta = b^2 - 4ac\\\\\Delta = (-3)^2 - 4.1.(-4)\\\\\Delta = 9 + 16\\\\\Delta = 25\\\\[/tex]
3) Nesta questão deve ser a soma dos coeficiente igual a 4.
[tex]x^2 + 2x + 1\\\\1 + 2 + 1\\\\3 + 1\\\\4\\[/tex]
[tex]4) x^2 - 4x = 0\\\\x.(x - 4) = 0\\\\x = 0\\\\x - 4 = 0\\\\x = 4\\\\(0 , 4)\\\\[/tex]
[tex]5) x^2 - 4 = 0\\\\x^2 = 4\\\\x = \pm\sqrt{4}\\ \\x = \pm2\\\\(2 ; -2)\\[/tex]
Veja mais em:
https://brainly.com.br/tarefa/18744845
https://brainly.com.br/tarefa/292422