Integral definida de -pi/2 até pi/2 (8t^2 + cos (t)) dt.... Pergunta de ideia deLara624

Lara624 @Lara624

November 2019 1 100 Report

Integral definida de

-pi/2 até pi/2 (8t^2 + cos (t)) dt

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Comentários (1) Π/2

∫ 8t² + cos (t) dt
-π/2

π/2
[ (8/3) *t³ +sen(t)] =(8/3)*(π/2)³ + sen(π/2) - (8/3)*(-π/2)³ - sen(-π/2)
-π/2

2*8π³/3 +2

=2*(8π³/3 +1)

=(2/3)* (8π³+3)

=22,67

2 votes Thanks 1

Lara624 Muito obrigada !

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