Articles
Register
Sign In
Search
JLucas2003
@JLucas2003
December 2019
2
58
Report
[40 pontos]Por favor, podem me responder a essa pergunta?
Determinar a P.A. em que se verificam as relações a5+a38=125 e a18+a22=116.
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
3478elc
a5+a38=125
a18+a22=116
a1 + 4r + a1+37r = 125 ==> 2a1 + 41r = 125
a1+17r+a1+21r = 116 ==> 2a1 + 38r = 116(-1)
2a1 + 41r = 125
-2a1 - 38r = -116
3r = 9 ==> r = 3
calculo de a1 :
2a1 + 41r = 125
2a1 = 125 - 41r ==> 2a1 = 125 - 41.3 ==>
2a1 = 125 - 123 ==> 2a1=2 ==> a1 = 1
(1,4,7, 10,13,16, 19,22,25, 28,31,34, 37,40,43, 46,49,52, 55,58,61,.....)
a18 + a2 ==> 52+64 = 116
1 votes
Thanks 1
Vi1984
A5 + (a5 + 33.r) = 125
2.a5 + 33r = 125 (I)
(a5 + 13.r) + (a5 + 17.r) = 116
2.a5 + 30.r = 116 (II)
(I) - (II):
3.r = 9
r = 3
2.a5 + 30.r = 116
2.a5 + 30.3 = 116
2.a5 = 116 - 90 = 26
a5 = 13
a5 = a1 + 4.r
13 = a1 + 4.3
a1 = 13-12 =1
PA:
(1,4,7,10,13,16,19,22,25,28.....)
0 votes
Thanks 1
More Questions From This User
See All
JLucas2003
December 2019 | 0 Respostas
Responda
JLucas2003
December 2019 | 0 Respostas
Responda
JLucas2003
December 2019 | 0 Respostas
Responda
JLucas2003
December 2019 | 0 Respostas
Responda
JLucas2003
December 2019 | 0 Respostas
Responda
JLucas2003
December 2019 | 0 Respostas
Responda
Recomendar perguntas
Deividyfreitas
May 2020 | 0 Respostas
BlackShot
May 2020 | 0 Respostas
Vanessakellen
May 2020 | 0 Respostas
Guiduarter
May 2020 | 0 Respostas
Mrzaine
May 2020 | 0 Respostas
O QUE SERIA AUTONOMIA?
Grazifer
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
a palavra rapidez formou se de qual derivacao
Celiana
May 2020 | 0 Respostas
Joazinho
May 2020 | 0 Respostas
Anatercia
May 2020 | 0 Respostas
×
Report "[40 pontos]Por favor, podem me responder a essa pergunta?Determinar a P.A. em que se verificam as re.... Pergunta de ideia de JLucas2003"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
a5+a38=125
a18+a22=116
a1 + 4r + a1+37r = 125 ==> 2a1 + 41r = 125
a1+17r+a1+21r = 116 ==> 2a1 + 38r = 116(-1)
2a1 + 41r = 125
-2a1 - 38r = -116
3r = 9 ==> r = 3
calculo de a1 :
2a1 + 41r = 125
2a1 = 125 - 41r ==> 2a1 = 125 - 41.3 ==>
2a1 = 125 - 123 ==> 2a1=2 ==> a1 = 1
(1,4,7, 10,13,16, 19,22,25, 28,31,34, 37,40,43, 46,49,52, 55,58,61,.....)
a18 + a2 ==> 52+64 = 116
2.a5 + 33r = 125 (I)
(a5 + 13.r) + (a5 + 17.r) = 116
2.a5 + 30.r = 116 (II)
(I) - (II):
3.r = 9
r = 3
2.a5 + 30.r = 116
2.a5 + 30.3 = 116
2.a5 = 116 - 90 = 26
a5 = 13
a5 = a1 + 4.r
13 = a1 + 4.3
a1 = 13-12 =1
PA:
(1,4,7,10,13,16,19,22,25,28.....)